Represented by the argument in octal (base 8). Returns: the string representation of the unsigned integer value Parameters: i - an integer to be converted to a string. String s by calling Integer.parseUnsignedInt(s, 8).įollowing characters are used as octal digits: In octal (base 8) with no extra leading 0s. toOctalString public static String toOctalString(int i).Since: JDK1.0.2 See Also: parseUnsignedInt(String, int), Represented by the argument in hexadecimal (base 16). Integer.toHexString(n).toUpperCase() Parameters: i - an integer to be converted to a string. These are the characters '\u0030' through Theįollowing characters are used as hexadecimal digits: Unsigned magnitude will not be the zero character. Otherwise, the first character of the representation of the If the unsigned magnitude is zero, it is represented by a String s by calling Integer.parseUnsignedInt(s, 16). The value of the argument can be recovered from the returned In hexadecimal (base 16) with no extra leading This value is converted to a string of ASCII digits If the argument is negative otherwise, it is equal to theĪrgument. The unsigned integer value is the argument plus 2 32 Returns a string representation of the integer argument as an toUnsignedString public static String toUnsignedString(int i,.Returns: a string representation of the argument in the specified radix. radix - the radix to use in the string representation. Integer.toString(n, 16).toUpperCase() Parameters: i - an integer to be converted to a string. If uppercase letters areĭesired, the String.toUpperCase() method may The digits for hexadecimal (radix 16) areĠ123456789abcdef. The following ASCII characters are used as digits:Īre used as radix- N digits in the order shown. The representation of the magnitude will not be the zeroĬharacter. ( '\u0030') otherwise, the first character of Represented by a single zero character '0' The remaining characters of the result represent the magnitude Negative, no sign character appears in the result. If the first argument is negative, the first element of the Or larger than Character.MAX_RADIX, then the radix If the radix is smaller than Character.MIN_RADIX If you have any questions or comments, just leave a note in the Comments section below.Returns a string representation of the first argument in the I hope this Java String to int example has been helpful. If you want to convert strings to other Java primitive fields, for example, a long, use methods like Long.parseLong(), and so on.If you're interested in converting a String to an Integer object, use the valueOf() method of the Integer class instead of the parseInt() method.Integer.toString(int i) is used to convert in the other direction, from an int to a Java String.While I’m in this neighborhood, here are a few related notes about the String and Integer classes: In this example, I don’t really need to use the String class trim() method, but in a real-world program you should use it, so that's why I’ve shown it here. If the conversion attempt fails - for instance, if you try to convert the Java String fred to an int - the Integer parseInt method will throw a NumberFormatException, which you should handle in a try/catch block. ("NumberFormatException: " + nfe.getMessage()) Īs you can see from this example, the Integer.parseInt(s.trim()) method is used to convert from the string s to the integer i in this line of code: print out the value after the conversion the String to int conversion happens here String s = "fred" // use this if you want to test the exception below Here’s the source code for a complete example program that demonstrates the Java String to int conversion process, handling for a possible NumberFormatException: Example 2: A complete “String to int” example If it fails for any reason, the conversion will throw a NumberFormatException, so your code should be a little bit longer to account for this, as shown in the next example. If the String represented by the variable myString is a valid integer like “1”, “200”, and so on, it will be converted to a Java int. Ignoring the exception it can throw, all you need to convert a String to int is this one line of code: Example 1: A basic Java “String to int” conversion example For more information, see the following two examples. ParseInt converts the String to an int, and throws a NumberFormatException if the string can’t be converted to an int type. The most direct solution to convert a Java string to an integer is to use the parseInt method of the Integer class: Java String/int FAQ: How do I convert a Java String to an int? Solution
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